Considered Formula;
$$\text {i)}\quad W.d = F \times d$$ $$\qquad \text {Where}~~W.d \to Work~done,\quad F \to Force \\\qquad d \to Distance~moved$$ $$\text {ii)}\quad K.E = \frac {1}{2}mv^2$$ $$\qquad \text {Where}~~K.E \to Kinetic~energy,\quad m \to Mass \\\qquad v \to Velocity$$Example
Abu Nufayl lifts a sack of rice by a force of 250 N against gravity to 2 m high. Calculate his work done
Solution
Data given
Force (F) =250 N
Distance (d) = 2 m
Work done (W.d) =?
$$~~~~~~~~~~~~~~~~~~~~~~~~~~~~W.d = F \times d$$ $$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 250 \times 2$$ $$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 500~Joules$$
The work done by Abu Nufayl = 500 Joules
The aim of this experiment is to find the ratio P defined in part (d) by using a simple pendulum.
