A Screw Jack consist of a cylinder with a spiral ridge runs
round it. The spiral is called the thread (T) and the distance between two
adjacent threads is called the pitch (p) of the screw.
Consider the following diagram.
Consider the following diagram.
Mechanical
advantage of the screw jack
M.A = Load
Effort
Effort
Velocity ratio (V.R)
V.R = Circumference of circle of radius (R)
Pitch of screw
Pitch of screw
V.R = 2πr
P
P
Example 1
A screw jack with a pitch of 0.2cm and a handle of
length 50cm is used to lift a car of weight 1.2 x 104N. If the
efficiency of the screw is 30%, find:
a) The velocity ratio and
mechanical Advantage of the machine
b) The effort required to
raise the car
Solution
Date given.
Pitch
(p) = 0.2cm
Radius (r) = 50cm
Load (L) = 1.2 x104N
Efficiency of jack (ɛ) =30%
Velocity ratio (V.R) =?
Mechanical advantage (M.A) =?
Effort (E)=?
Radius (r) = 50cm
Load (L) = 1.2 x104N
Efficiency of jack (ɛ) =30%
Velocity ratio (V.R) =?
Mechanical advantage (M.A) =?
Effort (E)=?
From
a) Velocity ratio (V.R) =?
The Velocity ratio = 1570
From
The Mechanical advantage = 471
b) Effort (E) =?
From
The effort required
to raise the car = 25 .5 N
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