Considered Formula
i)R.D=Wa−WlWa−Ww Where R.D→Relative density,Wa→Weight in airWl→Weight in liquid,Ww→Weight in water ii)R.D=ρsρw Where R.D→Relative density,ρs→Density of substanceρw→Density of waterExample 1
A piece of glass weight in air 1.2N and 0.7N when completely immersed in water calculate it’s.
a)
Relative density
b) Density of glass
c) Volume of glass
(Density of water = 1g/cm3)
Solution
Data given
Weight in air (Wa) = 1.2 N
Weight in water (Ww) = 0.7 N
Density of water (ρw) = 1g/cm3
a)
Relative density (R.D) = ?
R.D=WaWa−Ww =1.21.2−0.7 =1.20.5 =1.2×100.5×10 =125 =2.4
The relative density = 2.4