Considered Formula
M=F×d Where M→Moment ofForce,F→Forced→Perpendicular distanceExample 1
A line of action of a force of 90 N acts at a perpendicular distance of 2.5 m, from a point. Find the moment of the force
Solution
Data given
Force (F) = 90 N
Perpendicular distance (d) = 2.5 m
Moment of force (M) =?
M=F×d =90×2.5 =225 Nm
The moment of the force = 225 Nm
Example 2
A man applied a force of 200 N acts at a perpendicular distance of 40 cm, from hinges to open a door. Find the moment of the force
Solution
Data given
Force (F) = 200 N
Perpendicular distance (d)=40cm=(40100) m=0.4mMoment of force (M) =?
M=F×d =200×0.4 =80 Nm
The moment of the force = 80 Nm
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