Considered Formula
$$M = F \times d$$ $$\quad\text {Where}~~M \to Moment ~of Force,\quad F \to Force \\\quad d \to Perpendicular~distance$$Example 1
A line of action of a force of 90 N acts at a perpendicular distance of 2.5 m, from a point. Find the moment of the force
Solution
Data given
Force (F) = 90 N
Perpendicular distance (d) = 2.5 m
Moment of force (M) =?
$$~~~~~~~~~~~~~~~~~~~~~~~~~~~~M = F \times d$$ $$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 90 \times 2.5$$ $$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 225~Nm$$
The moment of the force = 225 Nm
Example 2
A man applied a force of 200 N acts at a perpendicular distance of 40 cm, from hinges to open a door. Find the moment of the force
Solution
Data given
Force (F) = 200 N
$$\text {Perpendicular distance (d)}= 40 cm = \Biggl( \frac {40}{100}\Biggr)~m = 0.4 m$$Moment of force (M) =?
$$~~~~~~~~~~~~~~~~~~~~~~~~~~~~M = F \times d$$ $$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 200 \times 0.4$$ $$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 80~Nm$$
The moment of the force = 80 Nm
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