Considered Formula;
i)W=mg Where W→Weight,m→Massg→Acceleration due to gravity ii)ρ=m1−m0V Where ρ→Density,m0→Mass of empty bottlem1→Mass of bottle+liquidV→Volume iii)ρ=mV1−V0 Where ρ→Density,m→MassV0→Initial Volume,V1→Final VolumeExample 1
In an experiment to determine the density of liquid Y, Sophia a form IA student obtained the following; Mass of beaker is 500g, Mass of beaker and liquid is 600g and Volume of liquid is 25 cm3. Find the density
Solution
Data given
Mass of empty beaker (m0) = 500 g
Mass of empty beaker + liquid (m1) = 600 g
Volume (V) =25 cm3
Density (ρ) = ?
ρ=m1−m0V =600−50025 =10025 =4 g/cm3
The density of liquid Y = 4 g/cm3
Example 2
The mass of a solid object with an irregular shape is 40 g. The solid object is totally immersed in water of volume 50 cm3 containing in a measuring cylinder rise to 70 cm3. Calculate density of the body
Solution
Data given
Mass (m) = 40 g
Initial Volume (V0) = 50 cm3
Final Volume (V1) = 70 cm3
Density (ρ) = ?
ρ=4070−50 =4020 =2 g/cm3
The density of the body = 2 g/cm3
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